The question splits the random numbers into two groups. There are p positive numbers and n negative numbers, and p = n + 6.

Statement (1) is sufficient. This also splits the numbers into two groups, but not the same groups. We can use the information to deduce how many more numbers are greater than zero than greater than one, but because we've only been given differences up to this point, we can't find the actual total. For instance, if there are 10 positive numbers, there are 4 negatives. With a total of 14, that would be 8 greater than 1 and 6 less than 1.

That scenario works, but the differences will remain the same if you add 10 to each number: 20 positives, 14 negatives, 18 greater than 1, and 16 less than 1.

Statement (2) is also insufficient. We know nothing specific about the numbers beyond their range. The answer would be much different if the numbers were closely bunched around 0 and 1 (say, 0.01 or 1.03) than if they were spread further out (say, 3 and -5).

Taken together, we still don't have enough information. Given a set of numbers that consists of a mix of positives and negatives, you can simplify the matter by assuming that many of them could cancel out. For instance, if there are 10 positives and 4 negatives, you could say that 4 of the positives are each 2 and 4 of the negatives are each -2. (That's a sum of 0.) Then you only have to consider the sum of the 6 remaining numbers, not the group of 14 as a whole. It's too time-consuming to work out a pair of contradictory examples, but since we don't know anything about the size of the numbers, we could construct many different sets that fit the requirements that sum to 3.75. Choice (E) is correct.