Don't be put off by the unusual quadratic in the question stem; as it turns out, you don't have to factor it. (However, if you try, it isn't that tricky: realize that the constants have to be 1 and -1, so the factorization must be (3x - 1)(2x + 1).)

Statement (1) is insufficient: x could be either 0 or -3. If x = 0, 6x^2 + x - 1 = -1. If x = -3, 6x^2 + x - 1 = 6(9) + (-3) - 1 = 50.

Statement (2) is sufficient: if x = -3, 6x^2 + x - 1 = 50. Choice (B) is correct.