While we know that the perimeter of a square is four times the length of one of its sides, we don't know the relationship between the perimeter of a triangle and any one of its sides unless we know more details about the shape of the triangle.

Statement (1) is insufficient. If we call one of the legs of T, t, the perimeter is 2t + tr2. However, that doesn't help us compare the perimeter of the triangle to that of the square.

Statement (2) is also insufficient. If we call a side of S, s, the length of a diagonal of s is sr2. That's a little more than 1.4s, meaning that the diagonal is a little more than 1/3 of 4s, the perimeter of the square. If the length of the longest side of T is 1.4s, the perimeter of T could be greater than 4s if T is very close to an equilateral triangle. If the sides are 1.4s, 1.35s, and 1.35s, the perimeter is greater than 4s. If the sides, however, are 1.4s, s, and 0.8s, the perimeter is less than 4s.

Taken together, the statements are sufficient. From (1), we know that the longest side of the triangle is the hypotenuse. Thus tr2 = sr2, meaning that t = s. The perimeter of the square is 4s, which is equivalent to 4t, which is greater than 2t + tr2, so the answer to the question is "no." Choice (C) is correct.